erase_iter_iter.pass.cpp   [plain text]

//===----------------------------------------------------------------------===//
//
//                     The LLVM Compiler Infrastructure
//
// This file is dual licensed under the MIT and the University of Illinois Open
// Source Licenses. See LICENSE.TXT for details.
//
//===----------------------------------------------------------------------===//

// <deque>

// iterator erase(const_iterator f, const_iterator l)

#include <deque>
#include <cassert>

std::deque<int>
make(int size, int start = 0 )
{
    const int b = 4096 / sizeof(int);
    int init = 0;
    if (start > 0)
    {
        init = (start+1) / b + ((start+1) % b != 0);
        init *= b;
        --init;
    }
    std::deque<int> c(init, 0);
    for (int i = 0; i < init-start; ++i)
        c.pop_back();
    for (int i = 0; i < size; ++i)
        c.push_back(i);
    for (int i = 0; i < start; ++i)
        c.pop_front();
    return c;
};

void
test(int P, std::deque<int>& c1, int size)
{
    typedef std::deque<int> C;
    typedef C::iterator I;
    assert(P + size <= c1.size());
    std::size_t c1_osize = c1.size();
    I i = c1.erase(c1.cbegin() + P, c1.cbegin() + (P + size));
    assert(i == c1.begin() + P);
    assert(c1.size() == c1_osize - size);
    assert(distance(c1.begin(), c1.end()) == c1.size());
    i = c1.begin();
    int j = 0;
    for (; j < P; ++j, ++i)
        assert(*i == j);
    for (j += size; j < c1_osize; ++j, ++i)
        assert(*i == j);
}

void
testN(int start, int N)
{
    typedef std::deque<int> C;
    int pstep = std::max(N / std::max(std::min(N, 10), 1), 1);
    for (int p = 0; p <= N; p += pstep)
    {
        int sstep = std::max((N - p) / std::max(std::min(N - p, 10), 1), 1);
        for (int s = 0; s <= N - p; s += sstep)
        {
            C c1 = make(N, start);
            test(p, c1, s);
        }
    }
}

int main()
{
    int rng[] = {0, 1, 2, 3, 1023, 1024, 1025, 2047, 2048, 2049};
    const int N = sizeof(rng)/sizeof(rng[0]);
    for (int i = 0; i < N; ++i)
        for (int j = 0; j < N; ++j)
            testN(rng[i], rng[j]);
}