mul.b   [plain text]


scale = 20
for (i=0; i<10000; i++) {
  for (j=1; j<100; j++) b=i*j
}
b
for (i=0; i<10000; i++) {
  for (j=1000000000000000000000000000000000000000000000000000000000000000000; \
       j<1000000000000000000000000000000000000000000000000000000000000000100; \
       j++) b=i*j
}
b
quit